corrupt trustdb caused by commandline?
Atom Smasher
atom at smasher.org
Tue May 9 03:11:49 CEST 2006
this is weird...
i can run this:
gpg --list-public-keys smasher ; echo $?
all day long, and everything is fine (returns 0).
but when i close stdout:
gpg --list-public-keys smasher 1>&- ; echo $?
it works once and corrupts my trustdb. running it again returns "2".
gpg: /home/atom/.gnupg/trustdb.gpg: invalid record type 112 at recnum 1
if i change the "1" to a "2" (closing stderr instead of stdout), it works
fine. if i omit the "1" and leave it implied (still closing stdout) it
still causes problems.
this is even weirder... this works fine:
{ gpg --list-public-keys smasher ; } ; echo $?
but this causes problems:
{ gpg --list-public-keys smasher ; } >&- ; echo $?
why on earth would gpg choke because i'm redirecting stdout *outside* of
the curly braces??
i've only noticed this since upgrading to 1.4.3. i was previously running
1.4.2 and the didn't have any problems with the exact same command.
FreeBSD 5.4-RELEASE
gnupg-1.4.3 (libiconv-1.9.2_2, gettext-0.14.5_2)
--
...atom
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