Fri Dec 14 01:08:02 2001
-----BEGIN PGP SIGNED MESSAGE-----
On Thursday 13 December 2001 03:56, you wrote:
> On Wed, 12 Dec 2001, Len Sassaman wrote:
> > Any idea what would prompt this error?
> > gpg: Ohhhh jeeee: no decrypt() for 17
> > secmem usage: 2016/10528 bytes in 4/6 blocks of pool 10752/16384
> > Aborted
> Sent that too fast. I'm using 1.0.6, trying to decrypt a message
> encrypted to my public key 09AC0A6A.
I guess the 17 refers to the key algorithm. From doc/DETAILS:
17 = DSA (sometimes called DH, sign only)
So it seems that someone managed to encrypt a message with your
_signing_ key. But as a signing key is not intended to be used for
encryption gpg can't decrypt the message because there is no decrypt()
for algorithm 17.
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.0.6 (GNU/Linux)
Comment: For info see http://www.gnupg.org
-----END PGP SIGNATURE-----