Works from the command line, but I can't get it to work with PHP

[Adam Cadieux]

Thanks Ralf for your advice. I think I need to get my gpg correct befor=
e I
try to integrate it into PHP code.

So I wrote the following command, but it doesn't seem to be working. I =
get
the feeling that I am missing something basic.

echo 1234 | gpg -o encrypted.gpg --symmetric --passphrase-fd 0 < pass.t=
xt

The '1234' is the data I want to encrypt,

What I am really trying to do is something like this

echo $data | gpg -o encrypted_file.gpg --symmetric --passphrase-fd
$password

Cheers,


Adam Cadieux



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                      Ralf D=F6ring                                    =
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"Adam Cadieux" <acadieux@pcguardian.com> writes:

> I am trying to write a PHP script that will encrypt user data (4 numb=
ers)
> with a symmetric password, but I am having trouble.
>
> I have looked through the archives and have added:
> putenv("/home/encrypt/.gnupg");

This should be something like
putenv("GNUPGHOME=3D/home/encrypt/.gnupg").


> Also I have made sure that I have make all the files in .gnupg are
readable
>
> I can get this command to work:
> echo system("gpg --warranty --homedir /home/encrypt/.gnupg");
>
> But when I run this test line nothing happens:
>
> echo system("echo 1234 | /usr/bin/gpg -o file.gpg --symmetric --homed=
ir
> /home/encrypt/.gnupg", $password);

I`m not a PHP programmer, but assume this doesn`t work because gpg
needs a passphrase for symmetric encryption. You can`t just pass this
as a variable to the system function. According to the PHP
documentation the second parameter to system() ($password in your case)=

receives the return code of the called program. To pass the passphrase
to gpg I suggest using the --passphrase-fd option of gpg.

HTH,
Ralf

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