GnuPG with Java waitFor() method on Windows?
Joseph Bruni
jbruni@mac.com
Tue Jul 29 04:35:02 2003
It might be waiting for some input from your program. Add the --batch
and --no-tty options to make sure that it doesn't prompt you for
something. Does the secret key have a passphrase? If so, that's what
it's waiting for.
On Monday, July 28, 2003, at 06:55 PM, Ruke Wang wrote:
> I am trying to use java Runtime.getRuntime().exec() to call gnupg to
> decrypt
> encrypted file. However, even though the file is properly decrypted,
> waitFor() never returns. The problem does not occur while I tried to
> verify
> a signed data file. By the way, is Java SDK1.4 Gnupg compatible?
>
> Thanks,
> Ruke Wang
>
> Here is my code, quite simple:
>
> import java.io.*;
>
> public class LicenseXmlTest
> {
> public static void main(String[] args)
> {
> TestXml tester = new TestXml();
> tester.Verify("d:\\test\\test.key");
> }
> }
>
> class TestXml
> {
> private String ExpireDate;
>
> private static String gpg_cmd = "c:\\gnupg\\gpg ";
> private static String home_dir = "--homedir d:\\test ";
> private static String key_ring = "--keyring ppp.asc --secret-keyring
> sss.asc ";
> private static String decrypt_para = "--decrypt ";
> private static String output_para = "--output ";
> private static String license_file = "d:\\test\\test.txt ";
>
> public TestXml()
> {
> ExpireDate = new String("01/01/1970");
> }
>
> public boolean Verify(String infile)
> {
> try
> {
> String cmd = gpg_cmd + home_dir + key_ring +
> output_para + license_file + decrypt_para + infile;
> Process opengpg = Runtime.getRuntime().exec(cmd);
> System.out.println(cmd);
>
> opengpg.waitFor();
>
> return true;
> }
> catch(IOException e)
> {
> System.err.println("Verify() ioexception" +
> e.toString());
> return false;
> }
> catch (InterruptedException e)
> {
> System.err.println("Verify() interrupt" +
> e.toString());
> Thread.currentThread().interrupt();
> return false;
> }
> }
> }
>
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