Questions about generating keys (hash firewalls)
Robert J. Hansen
rjh at sixdemonbag.org
Fri Aug 24 22:00:50 CEST 2007
Oskar L. wrote:
> So if we start with Bob, we need to have 253 more people, to be able to
> make 253 different pairs of which Bob is part of.
We need 22 more people.
In a room of 23 people, there are C(23, 2) different pairs, or 253.
You should probably refresh your knowledge of combinatorics before
talking about the birthday paradox.
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