Questions about generating keys (hash firewalls)

[Robert J. Hansen]

Oskar L. wrote:
> So if we start with Bob, we need to have 253 more people, to be able to
> make 253 different pairs of which Bob is part of.

We need 22 more people.

In a room of 23 people, there are C(23, 2) different pairs, or 253.

You should probably refresh your knowledge of combinatorics before
talking about the birthday paradox.