How can I extract the --embedded-filename for scripting?

[Peter Lebbing]

> Do you see any way to get the embedded file name for variables?

I see two options.

One: get the name before you write the decrypted file. Since the name is
obviously encrypted, you do need your private key.

$ gpg --with-colons --list-packets foo.gpg
:pubkey enc packet: version 3, algo 1, keyid 26F7563E73A33BEE
        data: [2043 bits]
:encrypted data packet:
        length: 86
        mdc_method: 2
gpg: encrypted with 2048-bit RSA key, ID 73A33BEE, created 2009-11-12
      "Peter Lebbing <peter at digitalbrains.com>"
:compressed packet: algo=2
:literal data packet:
        mode b (62), created 1368011777, name="Hi Michael",
        raw data: 16 bytes

I created a file named "Hi Michael" filled with 16 bytes of randomness.

Two: get the name from status-fd during writing the decrypted file.

$ gpg --status-fd 1 --use-embedded-filename foo.gpg
[GNUPG:] ENC_TO 26F7563E73A33BEE 1 0
[GNUPG:] CARDCTRL 3
gpg: encrypted with 2048-bit RSA key, ID 73A33BEE, created 2009-11-12
      "Peter Lebbing <peter at digitalbrains.com>"
[GNUPG:] BEGIN_DECRYPTION
[GNUPG:] DECRYPTION_INFO 2 7
[GNUPG:] PLAINTEXT 62 1368011777 Hi%20Michael
[GNUPG:] PLAINTEXT_LENGTH 16
[GNUPG:] DECRYPTION_OKAY
[GNUPG:] GOODMDC
[GNUPG:] END_DECRYPTION

HTH,

Peter.

-- 
I use the GNU Privacy Guard (GnuPG) in combination with Enigmail.
You can send me encrypted mail if you want some privacy.
My key is available at <http://digitalbrains.com/2012/openpgp-key-peter>