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<p dir="auto">That looks like a N^2 behavior.</p>
<p dir="auto">What about</p>
<pre class="code highlight js-syntax-highlight plaintext" lang="plaintext" v-pre="true"><code><span id="LC1" class="line" lang="plaintext">if (have_null || have_srp || have_rsa_psk) {</span>
<span id="LC2" class="line" lang="plaintext"> for (i = j = 0; i < priority_cache->protocol.num_priorities; i++) {</span>
<span id="LC3" class="line" lang="plaintext"> vers = version_to_entry(priority_cache->protocol.priorities[i]);</span>
<span id="LC4" class="line" lang="plaintext"> if (!vers || !vers->tls13_sem)</span>
<span id="LC5" class="line" lang="plaintext"> priority_cache->protocol.priorities[j++] = priority_cache->protocol.priorities[i];</span>
<span id="LC6" class="line" lang="plaintext"> }</span>
<span id="LC7" class="line" lang="plaintext">}</span>
<span id="LC8" class="line" lang="plaintext">priority_cache->protocol.num_priorities = j;</span></code></pre>
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