ec subtract
Jakob Breier
j.breier at gmx.de
Thu Jul 10 23:46:54 CEST 2014
On 10.07.2014 21:12, Sree Harsha Totakura wrote:
> Or, you can add point B to point at infinity, (0, 1, 0) in jacobian
> coordinates, and then add the result to A to get A - B.
>
> So, this could be done as: A + B + INFINITY.
I don't usually follow this list, so there might be something really
strange with the implementation I don't know of, but the point at
infinity normally is the neutral element of the group. So A+B+Infinity =
A+B.
Regards,
Jakob
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