ec subtract

Sree Harsha Totakura sreeharsha at
Fri Jul 11 00:35:47 CEST 2014

On 07/10/2014 11:46 PM, Jakob Breier wrote:
> On 10.07.2014 21:12, Sree Harsha Totakura wrote:
>> Or, you can add point B to point at infinity, (0, 1, 0) in jacobian
>> coordinates, and then add the result to A to get A - B.
>> So, this could be done as: A + B + INFINITY.
> I don't usually follow this list, so there might be something really
> strange with the implementation I don't know of, but the point at
> infinity normally is the neutral element of the group. So A+B+Infinity =
> A+B.

Ah, I was wrong.  It has nothing to do with the implementation, what I
suggested wouldn't work.


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