Build error gnupg-1.9.17 on Debian

[Raphael Lechner]

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Hello

I have trouble to build the gnupg-1.9.17 on a Debian Sarge Machine.
First i have installed libassuan-0.6.10 without problem but when i build
gnupg the compiler exists with errors:

if i386-linux-gcc -DHAVE_CONFIG_H -I. -I. -I..  -I../gl -I../common
- -I../intl -DLOCALEDIR=\"/usr/share/locale\"
- -DGNUPG_BINDIR="\"/usr/bin\"" -DGNUPG_LIBEXECDIR="\"/usr/libexec\""
- -DGNUPG_LIBDIR="\"/usr/lib/gnupg\""
- -DGNUPG_DATADIR="\"/usr/share/gnupg\""         -I/usr/include -Wall -g
- -O2 -Wall -MT call-scd.o -MD -MP -MF ".deps/call-scd.Tpo" -c -o
call-scd.o call-scd.c; \
then mv -f ".deps/call-scd.Tpo" ".deps/call-scd.Po"; else rm -f
".deps/call-scd.Tpo"; exit 1; fi
call-scd.c: In Function »agent_scd_check_aliveness«:
call-scd.c:409: Warning: implicit declaration of function `assuan_set_flag'
call-scd.c:409: error: `ASSUAN_NO_WAITPID' undeclared (first use in this
function)
call-scd.c:409: error: (Each undeclared identifier is reported only once
call-scd.c:409: error: for each function it appears in.)
make[3]: *** [call-scd.o] Fehler 1
make[3]: Leaving directory `gnupg-1.9.17/agent'
make[2]: *** [all-recursive] Error 1
make[2]: Leaving directory `gnupg-1.9.17'
make[1]: *** [all] Error 2
make[1]: Leaving directory `gnupg-1.9.17'
make: *** [build-stamp] Error 2

Always the same error with gcc-2,95,gcc3.3,gcc3,4

What can i do ?

Thank you

Raphael Lechner