dshaw at jabberwocky.com
Tue Nov 6 05:27:36 CET 2007
On Mon, Nov 05, 2007 at 06:18:33PM +0100, Philipp Gühring wrote:
> Thanks for your answer!
> Ok, I need the following:
> 1. I need a tool that lists me all the UIDs in a key.
> 2. Then I select the UIDs I need, and the UIDs I do not need
> 3. Then I need a tool that removes all selected unneeded UIDs from the key,
> and returns me the stripped key.
> Until now I tried the do the first step with gpg --with-colons and the third
> step with gpg --edit-key by automating gpg.
> But due to the ordering problem, this doesn´t work.
The ordering does not matter. GPG supports selecting a user ID by hash:
gpg --with-colons --list-keys (whatever)
uid:-::::2006-08-02::A8DCEA454269C4701E724839B04AEDD404BC21EB::Foo Bar <foo at example.com>:
this is the hash value
gpg --edit-key (whatever)
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